NCERT Exemplar Solution of some basic concept of chemistry-Best IIT-JEE ,NEET Coaching In Varanasi.

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I can help explain some basic concepts in chemistry and guide you through solving problems similar to those you might find in the NCERT Exemplars. Let’s start with some foundational topics: Best IIT-JEE ,NEET Coaching In Varanasi.

1. Atoms and Molecules

Concept: Atoms are the smallest units of matter that retain the properties of an element. Molecules are formed when two or more atoms bond together. Best IIT-JEE ,NEET Coaching In Varanasi.

Example Problem:

  • Question: How many atoms are present in 2 molecules of water (H₂O)? Best IIT-JEE ,NEET Coaching In Varanasi.
  • Solution:
    • One water molecule (H₂O) contains 2 hydrogen atoms and 1 oxygen atom.
    • Therefore, 2 water molecules will contain 2×2=42 \times 2 = 42×2=4 hydrogen atoms and 2×1=22 \times 1 = 22×1=2 oxygen atoms.
    • Total atoms = 4 (H) + 2 (O) = 6 atoms. Best IIT-JEE ,NEET Coaching In Varanasi.

2. Mole Concept

Concept: A mole is a quantity used to count particles, such as atoms or molecules. One mole is equal to 6.022×10236.022 \times 10^{23}6.022×1023 particles (Avogadro’s number). Best IIT-JEE ,NEET Coaching In Varanasi.

Example Problem:

  • Question: How many molecules are there in 3 moles of CO₂? Best IIT-JEE ,NEET Coaching In Varanasi.
  • Solution:
    • 1 mole of CO₂ contains 6.022×10236.022 \times 10^{23}6.022×1023 molecules.
    • Therefore, 3 moles will contain 3×6.022×1023=1.8066×10243 \times 6.022 \times 10^{23} = 1.8066 \times 10^{24}3×6.022×1023=1.8066×1024 molecules. Best IIT-JEE ,NEET Coaching In Varanasi.

3. Chemical Reactions and Stoichiometry

Concept: Chemical reactions involve the transformation of reactants into products. Stoichiometry is used to determine the quantities of reactants and products involved in a reaction. Best IIT-JEE ,NEET Coaching In Varanasi.

Example Problem:

  • Question: Given the reaction 2H2+O2→2H2O2H_2 + O_2 \rightarrow 2H_2O2H2​+O2​→2H2​O, how many moles of water can be produced from 4 moles of hydrogen gas and excess oxygen?
  • Solution:
    • According to the balanced equation, 2 moles of H2H_2H2​ produce 2 moles of H2OH_2OH2​O.
    • Therefore, 4 moles of H2H_2H2​ will produce 42×2=4\frac{4}{2} \times 2 = 424​×2=4 moles of H2OH_2OH2​O. Best IIT-JEE ,NEET Coaching In Varanasi.

4. Acids and Bases

Concept: Acids are substances that donate protons (H⁺ ions) and bases are substances that accept protons. The strength of acids and bases is measured by their pH levels. Best IIT-JEE ,NEET Coaching In Varanasi.

Example Problem:

  • Question: What is the pH of a solution with a hydrogen ion concentration of 1×10−31 \times 10^{-3}1×10−3 M? Best IIT-JEE ,NEET Coaching In Varanasi.
  • Solution:
    • pH is calculated as −log⁡[H+]-\log [H^+]−log[H+].
    • For [H+]=1×10−3[H^+] = 1 \times 10^{-3}[H+]=1×10−3 M, pH = −log⁡(1×10−3)=3-\log (1 \times 10^{-3}) = 3−log(1×10−3)=3. Best IIT-JEE ,NEET Coaching In Varanasi.

5. Periodic Table and Periodicity

Concept: The periodic table organizes elements based on their atomic number and properties. Elements in the same group have similar chemical properties. Best IIT-JEE ,NEET Coaching In Varanasi.

Example Problem:

  • Question: What is the common property of elements in the same group of the periodic table? Best IIT-JEE ,NEET Coaching In Varanasi.
  • Solution:
    • Elements in the same group have similar valence electron configurations, leading to similar chemical properties. Best IIT-JEE ,NEET Coaching In Varanasi.

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